I’ve been set 2 questions, the first I have solved, but the second I am totally lost.
Question 2:
I want to create a sheet 800mm x 800mm x 2mm thick with 60% carbon fibre of density 1800kg/m3 and 40% of the dispersion polymer.
I have a dispersion that is 40% solids of polymer. The density of the polymer is 1100kg/m3. I use an activating agent to de-stabilise the yield (i.e the dispersion turns to a solid polymer lump and water, the water being discarded). The activated agent is added at a rate of 0.5% by weight on weight to create a premix solution. Once mixed it in turn needs to be added at a ratio of 5kg (activation agent solution) to every 1kg of solution weight of the dispersion.
How much carbon fibre and wet dispersion will I need and how much dry weight of the activation agent is required? (Assume the activation agent does not add the polymer weight of the final sheet and is only used as a transient processing aid)
ANSWER:
Carbon Fibre ?
Wet Dispersion ?
Activation Agent ?
Q1. I want to create a sheet 900mm x 900mm x 3mm thick. I wish to have a volume fraction of 55% carbon fibre & 45% PA6 resin. The density of carbon fibre is 1800kg/m3 and the density of PA6 is 1.14g/cc. How much carbon fibre will I need?
ANSWER: Carbon Fibre = 2.4057kg & PA6 Resin = 1.2466kg
Solution:
0.9m x 0.9m x 0.003m = 0.00243m2
Carbon Fibre % = 0.00243 x 0.55 = 0.0013365m3
PA6 Resin % = 0.00243 x 0.45 = 0.0010935m3
Carbon Density = 1800kg/m3
PA Resin = 1.14g/cc (convert to kg/m3) x 1000 = 1140kg/m3
Carbon Fibre required is 1800 x 0.0013365 = 2.4057kg
PA6 Resin is 1140 x 0.0010935 = 1.2466kg