I’m on the point to buy myself a Edwards RV8 pump for infusion.
Only there is one thing that I still don’t understand, thats very important.
How can I convert the mbar or torr to HG or Bar.
This are the numbers:
2 x 10-3 mbar / 1.5 x 10-3 Torr
3 x 10-2 mbar / 2.3 x 10-2 Torr
6 x 10-2 mbar / 4.6 x 10-2 Torr
Can somebody convert them for me and explain me how?
2 x 10^-3 mbar = 0,002 mbar = 0,000002 bar
3 x 10^-2 mbar = 0,03 mbar = 0,00003 bar
1 x 10^-2 = 0,01 (kwestie van komma 2 posities naar links verplaatsen (links, want -2 is negatief. Zou er 2 staan, dan komma naar rechts.
mbar = millibar (milli = 1 duizendste, vergelijk millimeter)
1000 mbar = 1 bar
Ik stuur je een berichtje.
Thanx, but there a lot of this sites and they don’t help me.
You can’t convert the figures that are standing in my post.
Thanx herman but i’m looking for the figures that are shown on a gauge. I want to know how much vacuum is displayed when its doing 0,002 or 0,006 mbar like writen above. Is it like 28,908 HG or -98,5326 Bar. And how do you get the figures?
Nobody who can explain it to me ?
mbar * .0295333727 = inHg
torr * .039374592 = inHg
mbar / 1000 = bar
torr * .00133322368 = bar
Thanx but this figures i already know. I want to know how much vacuum i can pul with this figures. The importent question is, does it pull more than 29 HG or -0,98 bar?
The max vacuum you can pull is theoretically 29.92 inHg or 1.01 bar but this will vary with elevation above sea level and will vary day to day due to changes in barometric pressure.
Thanx this is what i wanted to know. Can you alsow explain how to get the figures ?
These values are simply the average atmospheric pressure measured at sea level. They are measured values not calculated.
“Atmospheric pressure is the force per unit area exerted into a surface by the weight of air above that surface in the atmosphere of Earth”, according to Wikipedia.
So I didn’t understand it wright. I still don’t know how much vacuum i can pull with the figures i gave in the first post.
You are getting confused because the values you gave are referencing 0 absolute pressure (perfect vacuum) where a vacuum gauge typically references 0 as the local atmospheric pressure.
2 X 10-3 mbar (absolute) = .000059 inHg so if a perfect vacuum is 29.9246899 inHg the pump will pull 29.9246899 inHg - .000059inHg = 29.9246309 inHg
Does this make sense?
Now it make sence. I thought it would be something like that, and now you confirmed it. Thank you very much.
Bought 2,5 Edwards RV8 pumps today with a lot of stuf with it.
The pumps pull -1 bar on my gauge :D.
Thanx for the help everyone.
